Find the derivative of f(x)=∫1x2t3+1dtf(x) = \int_1^{x^2} \sqrt{t^3+1} dtf(x)=∫1x2t3+1dt.
2xx6+12x\sqrt{x^6+1}2xx6+1
x6+1\sqrt{x^6+1}x6+1
2xx3+12x\sqrt{x^3+1}2xx3+1
x3+1\sqrt{x^3+1}x3+1