Find the derivative of f(x)=ex−lnxf(x) = e^x - \ln xf(x)=ex−lnx (for x>0x > 0x>0).
ex−1xe^x - \frac{1}{x}ex−x1
ex+1xe^x + \frac{1}{x}ex+x1
xex−1−lnxxe^{x-1} - \ln xxex−1−lnx
ex−1x2e^x - \frac{1}{x^2}ex−x21