Find the curvature κ\kappaκ of y=x2y = x^2y=x2 at x=0x=0x=0. Given κ=∣f′′∣(1+(f′)2)3/2\kappa = \frac{|f''|}{(1+(f')^2)^{3/2}}κ=(1+(f′)2)3/2∣f′′∣.
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