Find the curvature κ\kappaκ of the curve y=ln(x)y = \ln(x)y=ln(x) at x=1x=1x=1. Formula: κ=∣f′′(x)∣(1+(f′(x))2)3/2\kappa = \frac{|f''(x)|}{(1+(f'(x))^2)^{3/2}}κ=(1+(f′(x))2)3/2∣f′′(x)∣.
1/21/21/2
1/(22)1/(2\sqrt{2})1/(22)
111
222\sqrt{2}22