Find the curvature κ=∣f′′(x)∣(1+(f′(x))2)3/2\kappa = \frac{|f''(x)|}{(1+(f'(x))^2)^{3/2}}κ=(1+(f′(x))2)3/2∣f′′(x)∣ of the function f(x)=lnxf(x) = \ln xf(x)=lnx at the point x=1x=1x=1.
111
1/21/21/2
1/221/2\sqrt{2}1/22
222\sqrt{2}22