Find the coordinates of the center of the circle x2+y2−8x+6y+16=0x^2 + y^2 - 8x + 6y + 16 = 0x2+y2−8x+6y+16=0.
(4,−3)(4, -3)(4,−3)
(−4,3)(-4, 3)(−4,3)
(4,3)(4, 3)(4,3)
(−4,−3)(-4, -3)(−4,−3)