Find the constant CCC for F(y)=∫(y2+6y)dyF(y) = \int (y^2 + 6y) dyF(y)=∫(y2+6y)dy if F(1)=4F(1) = 4F(1)=4.
C=1C = 1C=1
C=0C = 0C=0
C=23C = \frac{2}{3}C=32
C=103C = \frac{10}{3}C=310