Find the center of the circle (x−3)2+(y+2)2=49(x - 3)^2 + (y + 2)^2 = 49(x−3)2+(y+2)2=49.
(3,−2)(3, -2)(3,−2)
(3,2)(3, 2)(3,2)
(−3,2)(-3, 2)(−3,2)
(−3,−2)(-3, -2)(−3,−2)