Find the center of the circle x2+y2−6x+4y−3=0x^2 + y^2 - 6x + 4y - 3 = 0x2+y2−6x+4y−3=0.
(3,−2)(3, -2)(3,−2)
(3,2)(3, 2)(3,2)
(−3,2)(-3, 2)(−3,2)
(−3,−2)(-3, -2)(−3,−2)