Find the center and radius of the circle given by the equation x2+y2−4x+6y−3=0x^2 + y^2 - 4x + 6y - 3 = 0x2+y2−4x+6y−3=0.
Center (2,−3)(2, -3)(2,−3), radius 444
Center (−2,3)(-2, 3)(−2,3), radius 444
Center (2,−3)(2, -3)(2,−3), radius 161616
Center (4,−6)(4, -6)(4,−6), radius 444