Find the center and radius of the circle 2x2+2y2−8x+12y−10=02x^2 + 2y^2 - 8x + 12y - 10 = 02x2+2y2−8x+12y−10=0.
Center: (2,−3)(2, -3)(2,−3), Radius: 14\sqrt{14}14
Center: (2,−3)(2, -3)(2,−3), Radius: 262\sqrt{6}26
Center: (1,−32)(1, -\frac{3}{2})(1,−23), Radius: 142\frac{\sqrt{14}}{2}214
Center: (2,−3)(2, -3)(2,−3), Radius: 6\sqrt{6}6