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Integrals
medium
0:00.0
Find the area bounded by
y
=
z
2
−
2
z
y=z^2-2z
y
=
z
2
−
2
z
and
y
=
0
y=0
y
=
0
.
A
4
/
3
4/3
4/3
B
2
/
3
2/3
2/3
C
8
/
3
8/3
8/3
D
1
1
1
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