Find the arc length of y=x3/2y = x^{3/2}y=x3/2 for x∈[0,1]x \in [0, 1]x∈[0,1].
827(103/2−1)\frac{8}{27}(10^{3/2}-1)278(103/2−1)
23(103/2−1)\frac{2}{3}(10^{3/2}-1)32(103/2−1)
127(103/2−1)\frac{1}{27}(10^{3/2}-1)271(103/2−1)
103/210^{3/2}103/2