Find the absolute maximum and minimum of f(x)=x3−3x+1f(x) = x^3 - 3x + 1f(x)=x3−3x+1 on [−2,2][-2, 2][−2,2].
Max 333 at x=−1x=-1x=−1; Min −1-1−1 at x=1x=1x=1
Max 333 at x=2x=2x=2; Min −5-5−5 at x=−2x=-2x=−2
Max 333 at x=−1x=-1x=−1; Min −5-5−5 at x=−2x=-2x=−2... wait — check endpoints
Max 333 at x=−1x=-1x=−1; Min −1-1−1 at x=1x=1x=1, but also check f(−2)=−1f(-2)=-1f(−2)=−1 and f(2)=3f(2)=3f(2)=3