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GCD & LCM
hard
0:00.0
Find
gcd
(
n
3
−
1
,
n
2
−
1
)
\text{gcd}(n^3-1, n^2-1)
gcd
(
n
3
−
1
,
n
2
−
1
)
for
n
=
4
n=4
n
=
4
.
A
1
B
3
C
5
D
15
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