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GCD & LCM
hard
0:00.0
Find
GCD
(
n
3
−
1
,
n
2
−
1
)
\text{GCD}(n^3-1, n^2-1)
GCD
(
n
3
−
1
,
n
2
−
1
)
for
n
=
3
n=3
n
=
3
.
A
1
B
2
C
4
D
8
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