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Limits & Continuityhard
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Find lim⁡n→∞n+1−n1\lim_{n \to \infty} \frac{\sqrt{n+1} - \sqrt{n}}{1}limn→∞​1n+1​−n​​ (i.e., lim⁡n→∞(n+1−n)\lim_{n\to\infty}(\sqrt{n+1}-\sqrt{n})limn→∞​(n+1​−n​)).