Find dydx\frac{dy}{dx}dxdy by implicit differentiation for sin(xy)=x+y\sin(xy) = x + ysin(xy)=x+y.
1−ycos(xy)xcos(xy)−1\frac{1 - y\cos(xy)}{x\cos(xy) - 1}xcos(xy)−11−ycos(xy)
ycos(xy)−11−xcos(xy)\frac{y\cos(xy) - 1}{1 - x\cos(xy)}1−xcos(xy)ycos(xy)−1
Both (a) and (c)