Find ddx[(x2+1)(x3−3x)]\frac{d}{dx}[(x^2+1)(x^3-3x)]dxd[(x2+1)(x3−3x)].
5x4−6x2+3x2−3=5x4−3x2−35x^4 - 6x^2 + 3x^2 - 3 = 5x^4 - 3x^2 - 35x4−6x2+3x2−3=5x4−3x2−3
2x(x3−3x)+(x2+1)(3x2−3)2x(x^3-3x) + (x^2+1)(3x^2-3)2x(x3−3x)+(x2+1)(3x2−3)
5x4−3x2−35x^4 - 3x^2 - 35x4−3x2−3
Both (b) and (c) are correct