Find ddx[x2−4]\frac{d}{dx}[\sqrt{x^2 - 4}]dxd[x2−4] for ∣x∣>2|x| > 2∣x∣>2.
xx2−4\frac{x}{\sqrt{x^2-4}}x2−4x
2xx2−4\frac{2x}{\sqrt{x^2-4}}x2−42x
12x2−4\frac{1}{2\sqrt{x^2-4}}2x2−41
xx2−4−2\frac{x}{\sqrt{x^2-4}} - 2x2−4x−2