Find ddx[ln(sinx)]\frac{d}{dx}[\ln(\sin x)]dxd[ln(sinx)] for 0<x<π0 < x < \pi0<x<π.
cotx\cot xcotx
tanx\tan xtanx
1sinx\frac{1}{\sin x}sinx1
−cotx-\cot x−cotx