Find ddx[x2−1x+2]\frac{d}{dx}\left[\frac{x^2 - 1}{x + 2}\right]dxd[x+2x2−1].
x2+4x+1(x+2)2\frac{x^2 + 4x + 1}{(x+2)^2}(x+2)2x2+4x+1
2x(x+2)−(x2−1)(x+2)2\frac{2x(x+2) - (x^2-1)}{(x+2)^2}(x+2)22x(x+2)−(x2−1)
Both (a) and (c) — they're the same