Find ddx[1lnx]\frac{d}{dx}\left[\frac{1}{\ln x}\right]dxd[lnx1] for x>1x > 1x>1.
−1x(lnx)2-\frac{1}{x(\ln x)^2}−x(lnx)21
1x(lnx)2\frac{1}{x(\ln x)^2}x(lnx)21
−1xlnx-\frac{1}{x\ln x}−xlnx1
1xlnx\frac{1}{x\ln x}xlnx1