Find ddx[x2+13]\frac{d}{dx} [\sqrt[3]{x^2 + 1}]dxd[3x2+1].
2x3(x2+1)2/3\frac{2x}{3(x^2+1)^{2/3}}3(x2+1)2/32x
x3(x2+1)2/3\frac{x}{3(x^2+1)^{2/3}}3(x2+1)2/3x
23(x2+1)−1/3\frac{2}{3}(x^2+1)^{-1/3}32(x2+1)−1/3
13(x2+1)−2/3\frac{1}{3}(x^2+1)^{-2/3}31(x2+1)−2/3