Find ddx[∫0sinxet2dt]\frac{d}{dx} \left[ \int_0^{\sin x} e^{t^2} dt \right]dxd[∫0sinxet2dt] at x=π/2x = \pi/2x=π/2.
eee
000
eπ/2e^{\pi/2}eπ/2
111