Find ddx[cos−1(2x)]\frac{d}{dx} [\cos^{-1}(2x)]dxd[cos−1(2x)].
−21−4x2-\frac{2}{\sqrt{1 - 4x^2}}−1−4x22
21−4x2\frac{2}{\sqrt{1 - 4x^2}}1−4x22
−11−4x2-\frac{1}{\sqrt{1 - 4x^2}}−1−4x21
−21−x2-\frac{2}{\sqrt{1 - x^2}}−1−x22