Find d2ydx2\frac{d^2y}{dx^2}dx2d2y for the curve x2+4y2=4x^2 + 4y^2 = 4x2+4y2=4 (an ellipse).
−14y3-\frac{1}{4y^3}−4y31
−x4y-\frac{x}{4y}−4yx
−x2−4y216y3\frac{-x^2-4y^2}{16y^3}16y3−x2−4y2
−14y-\frac{1}{4y}−4y1