Find f−1f^{-1}f−1 for f(x)=x2+2f(x) = x^2 + 2f(x)=x2+2 on [0,∞)[0, \infty)[0,∞).
f−1(x)=x−2f^{-1}(x) = \sqrt{x-2}f−1(x)=x−2 for x≥2x \ge 2x≥2
f−1(x)=x+2f^{-1}(x) = \sqrt{x+2}f−1(x)=x+2
f−1(x)=x−2f^{-1}(x) = \sqrt{x} - 2f−1(x)=x−2
f−1(x)=(x−2)1/2f^{-1}(x) = (x-2)^{1/2}f−1(x)=(x−2)1/2