Find an eigenvector for eigenvalue λ=3\lambda = 3λ=3 of A=(3001)A = \begin{pmatrix} 3 & 0 \\ 0 & 1 \end{pmatrix}A=(3001)
(10)\begin{pmatrix} 1 \\ 0 \end{pmatrix}(10)
(01)\begin{pmatrix} 0 \\ 1 \end{pmatrix}(01)
(11)\begin{pmatrix} 1 \\ 1 \end{pmatrix}(11)
(31)\begin{pmatrix} 3 \\ 1 \end{pmatrix}(31)