Find all zzz such that z2=iz^2 = iz2=i.
z=1+i2z = \frac{1+i}{\sqrt{2}}z=21+i or z=−1+i2z = -\frac{1+i}{\sqrt{2}}z=−21+i
z=1+iz = 1 + iz=1+i or z=−1−iz = -1 - iz=−1−i
z=iz = iz=i or z=−iz = -iz=−i
z=0z = 0z=0 or z=1z = 1z=1