Find all values of xxx in the interval [0,2pi][0, 2pi][0,2pi] that satisfy the equation 2sin2(x)+3cos(x)−3=02sin^2(x) + 3cos(x) - 3 = 02sin2(x)+3cos(x)−3=0.
x=0x = 0x=0
x=pi/3x = pi/3x=pi/3
x=5pi/3x = 5pi/3x=5pi/3
x=2pix = 2pix=2pi