Find all values of nnn such that n2+3n+5n^2 + 3n + 5n2+3n+5 is divisible by 111111.
n≡2(mod11)n \equiv 2 \pmod{11}n≡2(mod11)
n≡6(mod11)n \equiv 6 \pmod{11}n≡6(mod11)
n≡4(mod11)n \equiv 4 \pmod{11}n≡4(mod11)
n≡9(mod11)n \equiv 9 \pmod{11}n≡9(mod11)