Find all real solutions to the equation 4x−6⋅2x+8=04^x - 6 \cdot 2^x + 8 = 04x−6⋅2x+8=0.
x=1x = 1x=1 and x=2x = 2x=2
x=2x = 2x=2 and x=4x = 4x=4
x=0x = 0x=0 and x=3x = 3x=3
x=1x = 1x=1 only