Events AAA and BBB satisfy: P(A)=0.4P(A) = 0.4P(A)=0.4, P(B)=0.5P(B) = 0.5P(B)=0.5, P(A∩B)=0.15P(A \cap B) = 0.15P(A∩B)=0.15. Are events AAA and BBB independent?
Yes, because P(A)+P(B)=0.9P(A) + P(B) = 0.9P(A)+P(B)=0.9
No, because P(A∩B)≠P(A)⋅P(B)P(A \cap B) \neq P(A) \cdot P(B)P(A∩B)=P(A)⋅P(B)
Yes, because P(A∣B)=P(A)P(A|B) = P(A)P(A∣B)=P(A)
Cannot determine without more information