Evaluate ∫1x2−4dx\int \frac{1}{x^2 - 4} dx∫x2−41dx.
14ln∣x−2x+2∣+C\frac{1}{4} \ln|\frac{x-2}{x+2}| + C41ln∣x+2x−2∣+C
12arctan(x/2)+C\frac{1}{2} \arctan(x/2) + C21arctan(x/2)+C
ln∣x2−4∣+C\ln|x^2-4| + Cln∣x2−4∣+C
None