Evaluate ddx[sin(x)cos(x)]\frac{d}{dx}[\sin(x)\cos(x)]dxd[sin(x)cos(x)].
cos(2x)\cos(2x)cos(2x)
sin(2x)\sin(2x)sin(2x)
cos2x+sin2x\cos^2 x + \sin^2 xcos2x+sin2x
0