Evaluate ddx[sin(x)⋅cos(x)]\frac{d}{dx}[\sin(x) \cdot \cos(x)]dxd[sin(x)⋅cos(x)].
cos2(x)−sin2(x)\cos^2(x) - \sin^2(x)cos2(x)−sin2(x)
cos(2x)\cos(2x)cos(2x)
Both a and b
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