Evaluate the integral ∫01x2(x3+1)5dx\int_0^1 x^2(x^3+1)^5 dx∫01x2(x3+1)5dx using the substitution u=x3+1u = x^3+1u=x3+1.
2118\frac{21}{18}1821
6318\frac{63}{18}1863
216\frac{21}{6}621
636\frac{63}{6}663