Evaluate the integral: ∫(x5−2x)dx\int (x^5 - 2x) dx∫(x5−2x)dx.
16x6−x2+C\frac{1}{6}x^6 - x^2 + C61x6−x2+C
15x5−x2+C\frac{1}{5}x^5 - x^2 + C51x5−x2+C
6x6−2x2+C6x^6 - 2x^2 + C6x6−2x2+C
16x6−2x2+C\frac{1}{6}x^6 - 2x^2 + C61x6−2x2+C