Evaluate the integral ∫ln(z)z2dz\int \frac{\ln(z)}{z^2} dz∫z2ln(z)dz using integration by parts.
−ln(z)z−1z+C-\frac{\ln(z)}{z} - \frac{1}{z} + C−zln(z)−z1+C
ln(z)z+1z+C\frac{\ln(z)}{z} + \frac{1}{z} + Czln(z)+z1+C
−ln(z)z2−1z2+C-\frac{\ln(z)}{z^2} - \frac{1}{z^2} + C−z2ln(z)−z21+C
ln(z)z2+1z2+C\frac{\ln(z)}{z^2} + \frac{1}{z^2} + Cz2ln(z)+z21+C