Evaluate the integral I=∫0∞lnxx2+a2 dxI = \int_{0}^{\infty} \frac{\ln x}{x^2+a^2} \, dxI=∫0∞x2+a2lnxdx for a>0a > 0a>0.
π2alna\frac{\pi}{2a} \ln a2aπlna
−π2alna-\frac{\pi}{2a} \ln a−2aπlna
πalna\frac{\pi}{a} \ln aaπlna
000