Evaluate the integral I=∫01x21−x2 dxI = \int_{0}^{1} \frac{x^2}{\sqrt{1-x^2}} \, dxI=∫011−x2x2dx by using the trigonometric substitution x=sin(θ)x = \sin(\theta)x=sin(θ).
\pi/4
\pi/2
1
0