Infinite Serieshard
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Evaluate the infinite product P = \prod_{n=2}^{\infty} \left(1 - \frac{1}{n^2}
ight), and determine the sum of the corresponding series S = \sum_{n=2}^{\infty} \ln\left(1 - \frac{1}{n^2}
ight).
Evaluate the infinite product P = \prod_{n=2}^{\infty} \left(1 - \frac{1}{n^2} ight), and determine the sum of the corresponding series S = \sum_{n=2}^{\infty} \ln\left(1 - \frac{1}{n^2} ight).