Evaluate the indefinite integral ∫3z2−6z+10dz\int \frac{3}{z^2-6z+10} dz∫z2−6z+103dz by completing the square.
3arctan(z−3)+C3\arctan(z-3) + C3arctan(z−3)+C
arctan(3z−9)+C\arctan(3z-9) + Carctan(3z−9)+C
3ln∣z2−6z+10∣+C3\ln|z^2-6z+10| + C3ln∣z2−6z+10∣+C
3z−3+C\frac{3}{z-3} + Cz−33+C