Evaluate the definite integral ∫00.5(4x2−1)dx\int_{0}^{0.5} (4x^2 - 1) dx∫00.5(4x2−1)dx.
−16-\frac{1}{6}−61
16\frac{1}{6}61
−13-\frac{1}{3}−31
13\frac{1}{3}31