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Foundations
hard
0:00.0
Evaluate
∑
n
=
1
4
(
2
n
−
n
)
\sum_{n=1}^{4} (2^n - n)
∑
n
=
1
4
(
2
n
−
n
)
.
A
20
20
20
B
22
22
22
C
24
24
24
D
26
26
26
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