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Foundations
hard
0:00.0
Evaluate
∑
k
=
1
3
(
2
k
+
1
)
\sum_{k=1}^{3} (2k + 1)
∑
k
=
1
3
(
2
k
+
1
)
.
A
12
12
12
B
15
15
15
C
9
9
9
D
18
18
18
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