Evaluate limn→∞n2(an−1−ln(a1/n))\lim_{n \to \infty} n^2 (\sqrt[n]{a} - 1 - \ln(a^{1/n}))limn→∞n2(na−1−ln(a1/n)).
(lna)2/2(\ln a)^2 / 2(lna)2/2
000
lna\ln alna
+infty+\\infty+infty