Evaluate limn→∞(1n2∑k=1n⌊kx⌋)\lim_{n \to \infty} \left( \frac{1}{n^2} \sum_{k=1}^{n} \lfloor kx \rfloor \right)limn→∞(n21∑k=1n⌊kx⌋) for a fixed x>0x > 0x>0.
xxx
x/2x/2x/2
x2/2x^2/2x2/2
000