Evaluate limn→∞1n∑k=0n−1ek/n\lim_{n \to \infty} \frac{1}{n}\sum_{k=0}^{n-1} e^{k/n}limn→∞n1∑k=0n−1ek/n.
e−1e - 1e−1
eee
111
1e\frac{1}{e}e1